Let us briefly recall what we have done so far. With respect to the
proof that is a basis, we have reduced the fact that it is a set
of generators
in section 8 to the verification of Proposition
8.1, which we just have completed.
Further we already know from section 6
that the axiom of a cellular coalgebra
is valid. It remains to show axiom
and the fact that is linearly independent.
Let us start with the latter task. It is clearly enough to
consider the case where
.
Let
be the field of fractions on and let be the
image of under the embedding of into
.
Any relation among elements of
with coefficients from is a relation
with coefficients from the field
too.
Thus, we only have to show
.
Now,
is the centralizer
coalgebra of the algebra
generated by the endomorphisms
and acting on
in the sense of [O2, Section 2].
Consequently, by the comparison theorem [O2, Theorem 3.3]
the dimension in question is the same as the dimension of the
centralizer algebra of
acting on
.
The latter dimension can be deduced from well-known results from the theory of quantum groups. We will use [CP, Theorem 10.2.5 ii, second statement]. The operator called there equals our thus . The application of the theorem shows that the centralizer of our algebra is identical to the image of the quantized universal enveloping algebra (QUE) corresponding to the Dynkin diagram under its action on . Now, by [CP, Proposition 10.1.13 and Theorem 10.1.14], the tensor space decomposes into irreducibles as a QUE-module because is transcendental over . These irreducibles are indexed by the highest weights of the symplectic group and their dimensions are the same as in the classical case. The weights occurring are the same as for the symplectic group as well and correspond precisely to the elements of the set from the definition of (cf. [O2, 7.1]). It follows from work of R.C. King that the dimensions of the irreducibles are just ([Ki],cf. [Do2]). Consequently, we obtain the required identity:
We now verify axiom . We abbreviate . Let where and . As is grouplike and a homomorphism of algebras we calculate using (20) that
Here, as in section 11, is the set of multi-indices that are -column-standard with respect to the usual order on (see section 8). Now, according to the straightening formula 8.1 (after application of ) to each and there is an element (unique by the linear independence of ) such that
We set
and obtain
This completes the verification of axiom and hence the proof of Theorem 7.1.